A shorter solution is possible with an ordered list (<ol>) if we're willing to ignore the untidy output:

  li:nth-child(3n), li:nth-child(5n) { list-style: none }
  li:nth-child(3n)::before { content: "Fizz" }
  li:nth-child(5n)::after { content: "Buzz" }

  $ curl -sS https://susam.net/code/web/css-fizz-buzz-ol.html | sed -n '/none/,/after/p' |  tr -d '[:space:]' 
  li:nth-child(3n),li:nth-child(5n){list-style:none}li:nth-child(3n)::before{content:"Fizz"}li:nth-child(5n)::after{content:"Buzz"}
  $ curl -sS https://susam.net/code/web/css-fizz-buzz-ol.html | sed -n '/none/,/after/p' |  tr -d '[:space:]' | wc -c
  129

• 12/05/2025

• cluckindan

  12/05/2025

      list-style-position: inside;

  • susam

    12/05/2025

    Yes! However, like I mentioned in my previous comment, corrections like this cancel out the number of bytes saved with the <ol>-based solution.

    I mean, the solution in the original post is 152 characters long.

    The <ol> based solution is 129 characters long. Shorter but uglier.

    If we add your correction, we get neater output, which is nice, but it comes at the cost of 30 additional characters in the minified code thereby making the solution 159 characters long.

      li { list-style-position: inside }
      li:nth-child(3n), li:nth-child(5n) { list-style: none }
      li:nth-child(3n)::before { content: "Fizz" }
      li:nth-child(5n)::after { content: "Buzz" }

145 using P instead of li.

<style> p{counter-increment:n} p:not(:nth-child(5n)):before{content:counter(n)} p:nth-child(3n):before{content:"Fizz"} p:nth-child(5n):after{content:"Buzz"} </style><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p>

• rebane2001

  12/05/2025

  im not sure how you counted that as 145, but here's 137 for the css

  <style>p{--n:counter(n);counter-increment:n;&:before{content:var(--n)};&:nth-child(5n){--n:"";&:after{content:"Buzz"}}&:nth-child(3n){--n:"Fizz"</style><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p><p>

104 :nth-child(3n){list-style:"Fizz"}:nth-child(5n){list-style:"Buzz"}:nth-child(15n){list-style:"FizzBuzz"}

data:text/html,<style>:nth-child(3n){list-style:"Fizz"}:nth-child(5n){list-style:"Buzz"}:nth-child(15n){list-style:"FizzBuzz"}</style><ol id=o><script>o.innerHTML='<li>'.repeat(99)</script>

• cefqrn

  12/06/2025

  89: :nth-child(3n)::marker{content:"Fizz"var(--b,)}:nth-child(5n){list-style:"Buzz";--b:"Buzz

  with help from @bulmenisaurus

• Metaboat

  12/06/2025

  103 :nth-child(3n){list-style:"Fizz"}:nth-child(5n){list-style:"Buzz"}:nth-child(15n){list-style:"FizzBuzz"

  • Metaboat

    12/06/2025

    98 :nth-child(5n){list-style:""}:nth-child(3n){list-style:"Fizz"}:nth-child(5n)::after{content:"Buzz"

    • Metaboat

      12/06/2025

      95 :nth-child(5n){list-style:}:nth-child(3n){list-style:"Fizz"}:nth-child(5n)::after{content:"Buzz

      • Metaboat

        12/06/2025

        68 :nth-child(3n){list-style:"Fizz"}:nth-child(5n)::after{content:"Buzz

        • bulmenisaurus

          12/06/2025

          This version fails for numbers like 5, showing "5. Buzz". In the case of a number divisible by 5 but not 3 nothing prevents the 5 in the ::marker from rendering.

          Edit: it looks like your version can be fixed into a working 85:

            :nth-child(5n){list-style:'';&:after{content:"Buzz"}}:nth-child(3n){list-style:"Fizz"

        • eurleif

          12/06/2025

          67 :nth-child(3n){list-style:"Fizz"}:nth-child(5n):after{content:"Buzz

          • Metaboat

            12/06/2025

            thank you sir! i can improve the html op css was 152, we have the whole page at 144

            data:text/html,<ol id=o><script>o.innerHTML='<li>'.repeat(100)</script><style>:nth-child(3n){list-style:"Fizz"}:nth-child(5n):after{content:"Buzz

            • throwaway150

              12/06/2025

              Your code is showing the numbers 5, 10, 20. that's not correct, is it?

              Yours prints 1. 2. Fizz 4. 5. Buzz Fizz 7.

              But it should be 1. 2. Fizz 4. Buzz Fizz 7.

Ignoring the size of the HTML in addition to the CSS, it’s fun, but not really fair when talking about code golf. Beyond a few numbers, you need to include some JavaScript and generating a million list elements. But those bytes count …

144, using css variables, with fallback and p instead of li

https://codepen.io/dsmmcken/pen/WbwYOEQ?editors=0100

p{counter-increment:n;--n:counter(n)}p:nth-child(3n){--f:"Fizz"}p:nth-child(5n){--b:"Buzz";--n:''}p::after{content:var(--f,var(--n))var(--b,'')}

I love this, it's a very clever and funny way to solve the problem. Makes me think about how there are infinite routes from A to B, some more scenic and whimsical than others.. as well as all the people I've met along the way who would be so pissed and pedantic about how this isn't a "real solution" LOL

• hyperhello

  12/05/2025

  The problem is that you have to define the problem enough to avoid the fact that it's trivial to output the string "1,2,Fizz,4,Buzz,......" and fulfill the assignment. You can, in fact, output "$1,$2,Fizz,$4,Buzz,..." where $ is any prefix itself divisible by 15 (there are other templates for the other situations but it clearly does repeat endlessly.)

• 12/05/2025

To nitpick a bit, I'd say there is something that is "placed outside the stylesheet".

Now, arguably it's not a "number or word that appears in the output", that's true, but it is a part of the logic of FizzBuzz. It's the fact that there are 100 and exactly 100 <li> elements in the HTML part.

I mean, it wouldn't be a correct FizzBuzz without precisely that HTML. Having exactly 100 <li> elements is implementing the part of the logic that a. loops, and b. stops at 100.

But of course this is just nitpicking, as I said ;)

• culi

  12/06/2025

  HTML is just the runtime of CSS

Am I the only one here who's never seen CSS counters before? Interesting feature, what are they useful for practically?